Here let horse -h ,kick-k , shoe- s
3h=30. Thus, h = 10
h+s+s= 18 ,thus 2s = 18-h,thus 2s= 18-10,
2s=8, s=4, thus s=4.
And next s-k= 2,. -k=2-s, -k=2-4,. -k=-2 , thus k=2 ( both negetive sign cancelled)
Thus at final
k+h×s = ?
But put all value h=10; s=4; k=2.
We get
2+10×4
According to BODMAS rule we solve in order of . First bracket,of,divide, multiple, addition, substrate.
Thus here we have only multiple and addition thus you first solve multiple and then addition.
Thus 2+10×4 = 2+40= 42.
Thus the answer is 42 .
it it the correct answer.
Air plz look at my explanation step by step on post
Here let horse -h ,kick-k , shoe- s
3h=30. Thus, h = 10
h+s+s= 18 ,thus 2s = 18-h,thus 2s= 18-10,
2s=8, s=4, thus s=4.
And next s-k= 2,. -k=2-s, -k=2-4,. -k=-2 , thus k=2 ( both negetive sign cancelled)
Thus at final
k+h×s = ?
But put all value h=10; s=4; k=2.
We get
2+10×4
According to BODMAS rule we solve in order of . First bracket,of,divide, multiple, addition, substrate.
Thus here we have only multiple and addition thus you first solve multiple and then addition.
Thus 2+10×4 = 2+40= 42.
Thus the answer is 42 .
bro u wrong 1shoes +1horst×1 megnet 1+10×2=21