(Solution to word problem question) Add the square of 9 to the product of the square roots of 25 and.....

in Education3 years ago

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Hope to enjoy yourself over there.

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Today am share you this simple way to solve any word problem question in mathematics.

This question was asked by my online students even due to my offline students.
The question stated below,

Add the square of 9 to the product of the square roots of 25 and 4, and divide the result by the square root of 100.

This question above look simple but some student finds it difficult to understand and interpret it.
Well, it is simple,
Look, at this lesson am sure you will know how to interpret it.

Topic: word problem
Reference book: essential mathematics.
Let start,

Firstly, read the question carefully and understand it.
Now,
Break it down like this.
1)square of 9= 9^2 =9×9=81
img_20211116_140427_1.jpg

  1. product square root of 25 and 4 = √25 × √4 =5×2=10

img_20211116_140318_0.jpg

Noted: there is a difference between square and square. As you can see above.

  1. square root of 100 =√100=10.
    img_20211116_140848_7.jpg
    ...
    As you can see now I have brake every down,
    Now, you can see is very simple.
    The next thing to do now, take all the interpretations together, by reading the question to put it together.
    See the question below.

Add the square of 9 to the product of the square roots of 25 and 4, and divide the result by the square root of 100.
,
After reading, now that you can interpret as below
10+81/10=91/10
That is 9.1
9*1/10.
img_20211116_140433_5.jpg

Therefore, the answer is 9.1

I hope you enjoy the explanation...

More exercise solution is more
Stay active.
Thanks.

In case you have any questions about any mathematics topic,
On this topic or else. Feel free to ask me in the Comment section.

First post here

https://read.cash/@Maxlucky/add-the-square-of-9-to-the-product-of-the-square-roots-of-25-and-4-and-divide-the-result-by-4a450bc0

https://read.cash/@Maxlucky/simple-logic-to-solve-any-mathematics-word-problem-95a6cd5c

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